Question 1039479
Write as 2^x+3^x-x^2-x^3, and set it equal to zero.

{{{graph(300,200,-10,10,-10,10,2^x+3^x-x^2-x^3)}}}
x=2.29 and x=3.23
check
4.89+12.38=5.24+12.00
17.27=17.24, within rounding error
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9.38+34.76=10.43+33.70
44.14=44.13, within rounding error.
{2.29,3.23}  These are discrete points.