Question 1039473
.
q(s)= square root 64-s^2   

Domain? -8 less or equal to s greater than or equal to 8? Is that what would be said for this problem?
~~~~~~~~~~~~~~~~~~~~~~~~~


<pre>
q(s) = {{{sqrt(64 - s^2)}}}.


The domain is those "s" for which {{{64 - s^2}}} >= {{{0}}}.


They are {s | -8 <= s <= 8},  or, in the interval notation, [-8,8].
</pre>