Question 1039445
Use the substitution, {{{u=x^2}}}
{{{u^2-10u+25=0}}}
{{{(u-5)^2=0}}}
{{{u-5=0}}}
{{{u=5}}}
{{{x^2=5}}}
{{{x=0 +- sqrt(5)}}}
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*[illustration dsa4.JPG].