Question 1039376
it starts with  y-k=a(x-h)^2

so entering the vertex, we have

y-2=a(x-3)^2

this reduces the choices to A or B. 

With a vertex at (3,2) and its focus below it, at (3,0), the parabola opens downward, and the 'a' value must be negative. Choice A is the only possible solution.