Question 1039431
a){{{g(h)=h+1=(x^2-1)+1=x^2}}}
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b){{{g(f)=(3x-2)^2-4=9x^2-12x+4-4=9x^2-12x}}}
{{{h(g(f))=(9x^2-12x)+2}}}
{{{h(g(f))=9x^2-12x+2}}}
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c) {{{h/g=(x+2)/(x^2-4)=1/(x-2)}}}
{{{f(h/g)=h/g+2}}}
{{{f(h/g)=1/(x-2)+2}}} where {{{x<>2}}}