Question 1039419
<pre><b>
{{{5-3x}}}{{{""=""}}}{{{2x^2}}}

Standard form is {{{Ax^2+Bx+C}}}{{{""=""}}}{{{0}}}
where A is a positive number.

{{{5-3x}}}{{{""=""}}}{{{2x^2}}}

Add -2x<sup>2</sup> to both sides

{{{5-3x-red(2x^2)}}}{{{""=""}}}{{{2x^2-red(2x^2)}}}

Rearrange terms in descending order on the left.
Right side becomes 0:

{{{-2x^2-3x+5}}}{{{""=""}}}{{{0}}}

Since first term is negative, multiply every term by -1:

{{{2x^2+3x-5}}}{{{""=""}}}{{{0}}}  <--- that's in standard form.  That's
                        all you were asked to do.  But
                        I'll go ahead and solve it.  

Factor the left side:

{{{(2x+5)(x-1)}}}{{{""=""}}}{{{0}}}

Use zero-factor property:

{{{2x+5}}}{{{""=""}}}{{{0}}};   {{{x-1}}}{{{""=""}}}{{{0}}}
  {{{2x}}}{{{""=""}}}{{{-5}}};    {{{x}}}{{{""=""}}}{{{1}}}
   {{{x}}}{{{""=""}}}{{{-5/2}}}

Edwin</pre></b>