Question 90090


      L has y-intercept (0, 2) and is perpendicular to the line with equation 
2x - 3y =6.


     Let the eq'n to the line L be y = Mx+c ........(1)
             its y- intercept  is (0,2)
           it is perpendicular to 2x-3y = 6 
               to find the slope  reduce it to std form -3y = -2x+6
                                                          y = 2x/3-2
                                 slope of the given eq'n = 2/3

                    hence slope for the line L is M = -1/m = -1/2/3 = -3/2

               to find the constant c we should substitute for y,M &x

                                    y = Mx+c 
                                    2 = -3/2(0)+c   or c = 2
      Therefore the required eq'n is y = -3x/2+2
       multiply by 2 throughout we get 2y = -3x+4