Question 1039383
{{{-1 + 10log(2,(4t+5))=19}}} 
{{{10log(2,(4t+5))=19+1}}}
{{{10log(2,(4t+5))=20}}}
divide both sides by 10
{{{log(2,(4t+5))=2}}}
The exponent equiv of logs
(4t+5) = 2^2
4t + 5 = 4
4t = 4 - 5
4t = -1
t = -1/4
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Check solution in the original equation
{{{-1 + 10log(2,(4(-1/4)+5))=19}}}
{{{-1 + 10log(2,(-1+5))=19}}}
{{{-1 + 10log(2,4)=19}}}
log base 2 of 4 is 2, therefore
-1 + 10(2) = 19