Question 1039284
9(x^2-2x)+1, rewritten.
9(x^2-2x+1)-9+1, completing the square, then subtracting the constant (multiplying by 9).

 
9(x-1)^2-8
vertex should be at (1,-8)
{{{graph(300,200,-10,10,-10,10,9x^2-18x+1)}}}
Check also by -b/2a for x, which is -(-18/18)=1
f(1)=-8