Question 1039271
In pure text,
(2x-1)/(x^2+2x-8)+2/(x+4)=1/(x-2)



Rendered to appear  {{{(2x-1)/(x^2+2x-8)+2/(x+4)=1/(x-2)}}}


Factoring the quadratic denominator {{{(2x-1)/((x+4)(x-2))+2/(x+4)=1/(x-2)}}}



First step is to multiply the left and right members by the simplest common denominator {{{(x+4)(x-2)}}}....


{{{(2x-1)(x-2)+2(x-2)=x+4}}}



... then continue to simplify and solve for x.
Be sure to check if found values work in the original equation.