Question 1038918
Consider the branching function 

{{{f(x) = -2x+4}}} for {{{ 0 < x <= 2}}}, and 

={{{((x-2)(x-5))/(x-7/2)^2}}} for {{{ 2 <x <= 5}}}.

The absolute minimum of this function is 0 and occurs at x = 2 and x = 5, and approaches {{{+infinity}}} as x approaches 7/2 from both sides.