Question 1039201
y=3x+1 if the first equation is equal to 0.
ky=(k-2)x+2
y=[(k-2)]/k +(2/k)
the two are parallel.
3 therefore equals (k-2)/k
3k=k-2, by cross-multiplication
2k=-2
k=-1
check
-3x+y+2=0
y=3x-2