Question 1039117
First find b(a).
{{{b(a)=sqrt(a-4)}}}
{{{b(a)=sqrt(3x+1-4)}}}
{{{b(a)=sqrt(3x-3)}}}
For the square root function, the argument cannot be negative so,
{{{3x-3>0}}}
{{{3x>3}}}
{{{x>1}}}
This is the domain of b(a).
({{{1}}},{{{infinity}}})