Question 1039096
A random sample of 1100 car owners in a particular city found 220 car owners who recieved a speeding ticket this year. Find a 95% confidence interval for the true percent of car owners in this city who recieved a speeding ticket this year. Express your results to the nearest hundredth of a percent.
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p-hat = 220/1100 = 0.2
ME = 1.96*sqrt[0.2*0.8/1100] = 0.024 
Answer: 

0.2 - 0.024% < p < 0.2 + 0.024%
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0.2024% < p < 0.2024%
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Cheers,
Stan H.
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