Question 1039079
 I'm having some difficulty w/ a problem that asks why this: 
f(x)=(x)/(x^2 + 2x - 3) creates the graph it does. I'm asked to include the asymptotes in my explanation which looks like -3 and and 1. I have the graph, but I'm unsure on how to explain it. 
Any help is greatly appreciated! 
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f(x) = x/[(x+3)(x-1)]
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Since the denominator becomes zero when x = -3 and again}}} when x = 1,
f(x) has vertical asymptotes at x = -3 and again at x = 1.
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The graph:::
{{{graph(400,400,-10,10,-10,10,x/(x^2+2x-3))}}}
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Cheers,
Stan H.
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