Question 1039037
suppose you were solving a quadratic equation to find the x-intercepts for a quadratic function and you came to no real solutions. what does this mean about the x-intercepts for the parabola and how does it affect the parabola.
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No real solutions --> no x-intercepts.
The graph of the parabola would have all points above (or below) the x-axis.
eg, y = x^2 + 1