Question 90028
{{{((3a+6)/(2a+2))*((a^2-a-2)/(a^2-4))}}}

1- We're gonna start by factorising the first part 
{{{((3a+6)/(2a+2))=(3(a+2)/2(a+1))}}}

2- Let factorise the second part,
{{{(a^2-a-2)=(a+1)(a-2)}}}
{{{(a^2-4)=(a+2)(a-2)}}}
and so, {{{(a+1)(a-2)/(a+2)(a-2) = (a+1)/(a+2)}}}

whence,
{{{3(a+2)/2(a+1)*(a+1)/(a+2) = 3/2}}}