Question 1038998
h is the input to g.
{{{g(h(x))=((4-x)+1)/((4-x)-2)}}}


{{{g(h(x))=(4-x+1)/(4-x-2)}}}


{{{(5-x)/(2-x)}}}



Then evaluate {{{g(h(-3))=(5-(-3))/(2-(-3))}}}.


{{{(5+3)/(2+3)}}}


{{{highlight(8/5)}}}