Question 1038910
.
x^2 +2 =2x
the value of x^4 -x^3 +x^2 +2
explain clearly
a)0
b)1
c)-1
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<pre>
  {{{x^4 -x^3 +x^2 +2}}} =                  (make grouping)  --->

= {{{(x^4 -x^3)}}} + {{{(x^2 +2)}}}              (replace {{{x^2 +2}}} by 2x, according to the condition)  --->

= {{{(x^4 -x^3) + 2x}}}                     (distract and add {{{x^3}}})  --->

= {{{(x^4 -2x^3)}}} + {{{(x^3+2x)}}} = 

= {{{(x^4 -2x^3)}}} + {{{x(x^2+2)}}} =          (replace {{{x^2 +2}}} by 2x, according to the condition)  --->

= {{{(x^4 -2x^3) + x*2x}}} = 

= {{{(x^4 -2x^3) + 2x^2}}} =                (make re-grouping)  --->

= {{{(x^4 +2x^2) - 2x^3}}} =

= {{{x^2(x^2 +2) - 2x^3}}} =               (replace {{{x^2 +2}}} by 2x, according to the condition)  --->

= {{{x^2*2x - 2x^3}}} = {{{2x^3 - 2x^3}}} = 0.

<U>Answer</U>.  0  (zero).
</pre>

Solved.