Question 1038879
Solve by two methods, quadratic equation and factoring:
2x^2-x-15=0
<pre>I would use the factoring method 1st, since it's easier, and you can use the solution(s) to check the solution(s) after using
the quadratic equation formula
{{{2x^2 - x - 15 = 0}}}
{{{2x^2 - 6x + 5x - 15 = 0}}} ------- Replacing - x with - 6x + 5x
{{{2x(x - 3) + 5(x - 3) = 0}}}
{{{(2x + 5)(x - 3) = 0 }}}
2x + 5 = 0      OR       x - 3 = 0
{{{highlight_green(matrix(1,3, x = - 5/2, or, x = 3))}}}