Question 1038812
<font face="Times New Roman" size="+2">


Clearly, if *[tex \Large x\ =\ 0] then you have no box since the area cut out of the corners is zero.  If you cut 5-inch squares out of the corners of a 10 by 40-inch piece of cardboard, then you would have a 10-inch by 30-inch piece of cardboard that you would fold in half lengthwise.  Again, no box.  Cutting a 20-inch square out of the corner of a 10 X 40 piece of material is impossible.  You can go 20 inches along the 40-inch dimension, but you can't go 20 inches the other way.  Anything between 0 and 5, NOT inclusive, makes a box, but there is only one value that gives you a maximum volume in that interval.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

</font>