Question 1038842
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Let *[tex \Large x] represent the number of years since 1988, so *[tex \Large x\ =\ 0] represents 1988 and *[tex \Large x\ =\ 16] represents 2004.  Now you can form two ordered pairs:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (0, 534000)]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (16, 496000)]


Use the Two-Point Form to find your equation.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ \left(\frac{y_1\ -\ y_2}{x_1\ -\ x_2}\right)(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the given points.


Once you have your equation, let *[tex \Large y\ =\ 450,000], solve for *[tex \Large x], and then calculate *[tex \Large x\ +\ 1988]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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