Question 1038718
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{{{4*sin2(4x)}}} = {{{2}}}
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I came to fix an error in the previous solution:


<pre>
{{{4*sin^2(4x)}}} = {{{2}}}

{{{sin^2(4x)}}} = {{{1/2}}}

sin(4x) = ą{{{sqrt(1/2)}}} = +/-{{{sqrt(2)/2}}}

4x = ąpi/4 + n*pi, n = any integer

x = ąpi/16 + n*pi/4, n = any integer    (x in radians)
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