Question 1038727
.
Solve
sqrt(x+5)+sqrt(x+10)>=2
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<TABLE> 
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  <TD> 

{{{graph( 330, 330, -10.5, 20.5, -10.5, 10.5,
          sqrt(x+5)+sqrt(x+10), 2
)}}}


<B>Figure</B>. Plots y = {{{sqrt(x+5)+sqrt(x+10)}}} and y = 2.

  </TD>
  </TR>
</TABLE>

Why not? - They are . . . 


Take x = -5. Then


{{{sqrt(x+5)+sqrt(x+10)}}} = {{{sqrt(0) + sqrt(5)}}} = {{{sqrt(5)}}} is just > 2.


Then everything that is greater than -5 satisfies the inequality, too.


<U>Answer</U>. The entire domain {x| x >= -5} is the solution.



Simply there is an error in the previous solution.