Question 1038727
Solve
sqrt(x+5)+sqrt(x+10)>=2 
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Square both sides to get::
x+5 + sqrt[(x+5)(x+10)] + x+10 >= 4
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sqrt[x^2+15x+50] >= -2x - 11
sqrt[x^2+15x+50] >= -(2x+11)
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Square both sides to get:
x^2 + 15x + 50 >= 4x^2 + 44x + 121
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3x^2 + 29x + 71 <= 0
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Ans:: no solution
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Cheers,
Stan H.
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