Question 1038733
Use a common denominator, {{{5(x-2)}}}
{{{(5*3)/(5(x-2))+(4(x-2))/(5(x-2))=27/(5(x-2))}}}
{{{15/5(x-2)+(4x-8)/(5(x-2))=27/(5(x-2))}}}
{{{(15+4x-8)/(5(x-2))=27/(5(x-2))}}}
{{{(4x+7)/(5(x-2))=27/(5(x-2))}}}
Equating numerators,
{{{4x+7=27}}}
{{{4x=20}}}
{{{x=5}}}