Question 1038677

Find the vertex  and than graph

2x^2+8x+16=0
By using:

X= -b/2a
<pre>{{{2x^2 + 8x + 16 = 0}}}
{{{2(x^2 + 4x + 8) = 2(0)}}} -------- Factoring out GCF, 2
{{{x^2 + 4x + 8 = 0}}}
{{{matrix(1,4, x-coordinate, of, "vertex:", - b/(2a) = - 4/(2 * 1) = - 4/2 = - 2)}}}
{{{matrix(1,4, y-coordinate, of, "vertex:", (- 2)^2 + 4(- 2) + 8 = 4 - 8 + 8 = 4)}}}
Vertex: {{{matrix(1,3, "(- 2", ",", "4)")}}}
{{{graph(300,300,-15,15,- 14,100,x^2 + 4x + 8)}}}