Question 1038690
the expected value is 1500*0.65=975 times=np
the variance is np(1-p)=975*0.35=341.25
the sd is the sqrt (341.25)=18.47
So, this can be approximated by a normal distribution
z=(960-975)/18.47=-0.812
z=(1000-975)/18.47=1.353
The probability is that part between these two z-values
it is 70.36% or 0.7036