Question 1038669
there are 10 sedans out of 32 for the first draw, therefore the probability that the first vehicle drawn will be a sedan is 10/32.


there are 9 sedans left out of 31 for the second draw, therefore the probability that the second vehicle drawn will be a sedan is 9/31.


the probability that a sedan is drawn on the first draw and then on the second draw is therefore 10/32 * 9/31 = 90/992.