Question 1038647
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This is just an arithmetic problem.


For -2, calculate *[tex \Large y\ =\ -2(-2)^2\ +\ 3], then the ordered pair is *[tex \Large (-2,y)] where *[tex \Large y] is the value you just calculated.  Repeat for each of the other values.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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