Question 1037372
Let {{{P(t) = P[0]*(1+r)^t}}}, where {{{P[0]}}} is the initial count, and r is the relative growth rate.

==> {{{P(2) = 200 = P[0]*(1+r)^2}}}  and  {{{P(8) = 24000 = P[0]*(1+r)^8}}}

Dividing the second equation by the first equation (effectively canceling {{{P[0]}}}), we get

{{{120 = (1+r)^6}}}

==> {{{r = root(6,120) - 1 = 1.220906}}}.

Therefore the relative growth rate r is 122.0906%.