Question 1038462
It is a 2,3,sqrt(13) triangle
tangent is opp/adj=(2/3)
sine is opp/hyp=2/sqrt (13)
Add them: common denominator is 3sqrt(13); numerator is 2 sqrt (13)+6,

[2 sqrt(13)+6]/3*sqrt(13)
after rationalizing the denominator
sqrt(13)(2sqrt(13)+6sqrt(13)]/39; the 39 comes from 3*sqrt(13)(sqrt (13)
[26+6 sqrt(13)]/39.  It may be written other ways.