Question 89920


     The length of a rectangle is 2 inches more than twice its width. If the perimeter of the rectangle is 34 inches, find the dimensions of the rectangle

    Let the width of the rectangle = w = x  inch
        the length of the rectangle = l = 2x+2   inch

                   perimeter of the rectangle = p = 34 inch

                                         p = 2(l+w)

                                        34 = 2(2x+2+x)
                                        34/2 = 3x+2
                                          17-2 = 3x 
                                             15 = 3x
                                              x = 15/3 = 5 

                                           width  = 5  inch
                                           length = 2*5+2 = 10+2 = 12 inch