Question 1038315
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a<sub>1</sub> = -3, a<sub>n</sub> = 2&#8729;a<sub>n-1</sub>

Let n = 2

a<sub>2</sub> = 2&#8729;a<sub>2-1</sub>
a<sub>2</sub> = 2&#8729;a<sub>1</sub>
a<sub>2</sub> = 2&#8729;(-3)
a<sub>2</sub> = -6

Let n = 3

a<sub>3</sub> = 2&#8729;a<sub>3-1</sub>
a<sub>3</sub> = 2&#8729;a<sub>2</sub>
a<sub>3</sub> = 2&#8729;(-6)
a<sub>3</sub> = -12

Let n = 4

a<sub>4</sub> = 2&#8729;a<sub>2-1</sub>
a<sub>4</sub> = 2&#8729;a<sub>1</sub>
a<sub>4</sub> = 2&#8729;(-12)
a<sub>4</sub> = -24

So far we have only four terms: -3, -6, -12, -24, __, __

Now you finish. Let n = 5 and n = 6 to find the 
remaining two terms you were to find. 

Edwin</pre></b></font>