Question 1038305
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We want an equation of this form

{{{sqrt("expression1")}}}{{{""+""}}}{{{sqrt(expression2)}}}{{{""=""}}}{{{"expression3"}}}

That's "something + something = something"

Let's make up a simple addition or subtraction example 
as a model like this simple addition example:

                          3 + 4 = 7

We want {{{sqrt("expression1")}}} to equal 3 when x=1
We want {{{sqrt("expression2")}}} to equal 4 when x=1
We want {{{"expression3"}}} to equal 7 when x=1

Let's create an expression1:
{{{sqrt("expression1")}}}{{{""=""}}}{{{3}}}
Squaring both sides:
{{{"expression1"}}}{{{""=""}}}{{{9}}}

Start with x = 1
Multiply through by something, say 4
          4x = 4
Add enough to both sides to make the right side come out to 9.
So we add 5 to both sides
        4x+5 = 9

So 4x+5 will do for expression1

Let's create an expression2:
{{{sqrt("expression2")}}}{{{""=""}}}{{{4}}}
Squaring both sides:
{{{"expression2"}}}{{{""=""}}}{{{16}}}

Start with x = 1
Multiply through by something, say 5
          5x = 5
Add enough to both sides to make the right side come out to 16.
So we add 11 to both sides
        5x+11 = 5+11
        5x+11 = 16

So 5x+11 will do for expression2

Let's create an expression3:
It's not a radical. We want it to equal 7 when 1
is substituted for x

Start with x = 1
Multiply through by something, say 8
          8x = 8
Subtract enough from both sides to make the right side come out to 7.
So we subtract 1 from both sides
        8x-1 = 8-1
        8x-1 = 7

So 8x-1 will do for expression3


{{{sqrt("expression1")}}}{{{""+""}}}{{{sqrt(expression2)}}}{{{""=""}}}{{{"expression3"}}}

becomes this equation

{{{sqrt(4x+5)}}}{{{""+""}}}{{{sqrt(5x+11)}}}{{{""=""}}}{{{8x-1}}}

Edwin</pre></b>