Question 89935


  . The length of a rectangular playing field is 5 ft less than twice its width.
If the perimeter of the playing field is 230 ft, find the length and width of the field

       Let the width of the rectanglular field be = x  ft
       Then length of the rectanglular  field = 2x-5   ft
         perimeter of the field  is           = 230 ft
                                   perimeter = 2(length+width)
                                         230 = 2(2x-5+x)
                                         230/2 = 3x-5
                                         115 +5 = 3x
                                          120   = 3x 
                                            120/3 = x
                                             x = 40 ft
                          width of the rectangular field = 40 ft
                          Length of the rectangular field = 75 ft  (2*40-5= 80-5=75)