Question 1038294
Plug in various values of x to get corresponding values of y

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Plug in x = -5
y = |x - 3|
y = |-5 - 3|
y = |-8|
y = 8
So (-5,8) is one point on this function graph.

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Plug in x = -4
y = |x - 3|
y = |-4 - 3|
y = |-7|
y = 7
So (-4,7) is one point on this function graph.

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Plug in x = -3
y = |x - 3|
y = |-3 - 3|
y = |-6|
y = 6
So (-3,6) is one point on this function graph.

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Plug in x = -2
y = |x - 3|
y = |-2 - 3|
y = |-5|
y = 5
So (-2,5) is one point on this function graph.

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Plug in x = -1
y = |x - 3|
y = |-1 - 3|
y = |-4|
y = 4
So (-1,4) is one point on this function graph.

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Plug in x = 0
y = |x - 3|
y = |0 - 3|
y = |-3|
y = 3
So (0,3) is one point on this function graph.

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Plug in x = 1
y = |x - 3|
y = |1 - 3|
y = |-2|
y = 2
So (1,2) is one point on this function graph.

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Plug in x = 2
y = |x - 3|
y = |2 - 3|
y = |-1|
y = 1
So (2,1) is one point on this function graph.

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Plug in x = 3
y = |x - 3|
y = |3 - 3|
y = |0|
y = 0
So (3,0) is one point on this function graph.

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Plug in x = 4
y = |x - 3|
y = |4 - 3|
y = |1|
y = 1
So (4,1) is one point on this function graph.

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Plug in x = 5
y = |x - 3|
y = |5 - 3|
y = |2|
y = 2
So (5,2) is one point on this function graph.

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The list of points are
(-5,8)
(-4,7)
(-3,6)
(-2,5)
(-1,4)
(0,3)
(1,2)
(2,1)
(3,0)
(4,1)
(5,2)
which makes this table:

<table border=1 cellpadding=3><tr><th>x</th><th>y</th></tr><tr><td>-5</td><td>8</td></tr><tr><td>-4</td><td>7</td></tr><tr><td>-3</td><td>6</td></tr><tr><td>-2</td><td>5</td></tr><tr><td>-1</td><td>4</td></tr><tr><td>0</td><td>3</td></tr><tr><td>1</td><td>2</td></tr><tr><td>2</td><td>1</td></tr><tr><td>3</td><td>0</td></tr><tr><td>4</td><td>1</td></tr><tr><td>5</td><td>2</td></tr></table>


Plotting all the points on the same xy grid will give this
<img src = "http://i.imgur.com/JedPBYF.png">
Draw a line/curve through all the points to get this function
<img src = "http://i.imgur.com/PntHAN3.png">
which is the graph you're looking for