Question 1038133
The square of the A leg is the hypotenuse squared minus 36, B squared
That is 4x^2-24x+36-36=4x^2-24x
A^2=4x^2-24x
A= sqrt (4x^2-24x)
This must be greater than 0, 4x^2>24x, x>6, 
Therefore, x must be greater than (6); 
There are infinite possibilities greater than (6)

if x=7, we have a 6, sqrt(28) and 8 triangle, the squares on both sides=64
if x=10, we have a 6,  sqrt (160) and 14 triangle.
If two sides are both x, there are infinite ways they can work to form a right triangle. They still have to fit with the Pythagorean theorem.