Question 89899
if the larger of two integers whose sum is 88 is divided by the smaller the quotient is 5 and the remainder is 10. what are the 2 nos.?
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Let the two integers be x and 88-x
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EQUATION: (88-x)/x = 5 + 10/(x
Multiply thru by x to get:
88-x = 5x + 10
6x = 78
x= 13 (one of the numbers)
88-x= 75 (the other number)
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Cheers,
Stan H.