Question 1038016
The height of a triangle is One inch more than twice its base. The Area
is 18 inches squared. Find the dimensions (base and height) of the triangle.
Set up and solve using Algebraic Equation.
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Area = b*h/2 = 18
b*h = 36
h = 2b + 1
b*(2b+1) = 36
2b^2 + b - 36 = 0
(2b+9)*(b-4) = 0
b = 4
h = 9
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Ignore the negative solution.