Question 89839
Solve the following equation for Y: (square root of)2Y+ 3= 11
:
{{{sqrt(2y)}}} + 3 = 11
:
{{{sqrt(2y)}}} = 11 - 3
:
{{{sqrt(2y)}}} = 8
:
Square both sides and you have:
2y = 64
:
y = 64/2
:
y = 32
:
:
Check solution:
{{{sqrt(2*32)}}} + 3 = 11
{{{sqrt(64)}}} + 3 = 11