Question 1037800
{{{p(X = x) = (mu^x/x!)e^(-mu)= (1.7^x/x!)e^(-1.7)}}} is the pmf for the Poisson r.v. X.

==> {{{p(X = 0) = (1.7^0/0!)e^(-1.7) = 0.1827}}}, to four significant figures.