Question 1037918
c) {{{lim( x->1, (x^10 - 2x + 1) / (x^4-1)) = lim( x->1, (10x^9 - 2) / (4x^3-1))
 = (10-2)/4 = 8/4 = 2}}}.  The second limiting expression was obtained by differentiating both numerator and denominator.  The initial indeterminate form was 0/0.

d) {{{lim( x->0, (5^x + 2x - 1) / (2^x - 1)) = lim( x->1, (ln5*5^x + 2) / (ln2*2^x )) = (ln5 + 2) / ln2 }}}.