Question 1037877
The sine is opposite over hypotenuse or -8/9
The other side must be the square root (17), so that the sum of the squares of the legs=square (hypotenuse)
That makes the cosine= +square root (17)/9, so the secant is 9*square root (17)/17, the reciprocal, after rationalization of the denominator.

The cotangent is cosine/sine, or sqrt(17)/9/-8/9, or - sqrt(17/8).