Question 1037859
{{{y=x^2+x-6=(x-2)(x+3)}}}
Zeros at x=2 and x=-3, and the vertex will be where {{{x=(2+(-3))/2=-1/2}}}.  Vertex is a minimum point in the graph.


{{{graph(300,300,-4,4,-7,2,x^2+x-6)}}}