Question 12934
No. it's not prime.  It can be factored.

Think! What are the factors of {{{15x^2}}}?  (3x)(5x), (x)(15x) and what are the factors of 4? (2)(2), (1)(4)

Try:  {{{(3x + 2)(5x + 2) = 15x^2 + 6x + 10x + 4}}} = {{{15x^2 + 16x + 4}}}