<PRE><B>Question 1037530</B>
 Ajax is 8km due west of Oshawa.
 Uxbridge is 16 km NW of Oshawa.
 How far is it from Ajax to Uxbridge?
:
One interior angle formed by the NW line to Ux is 45 degrees, therefore:
You can use the law of cosines: a^2 = b^2 + c^2 - 2bc*cos(A)
Where
A = 45 degrees,
a = dist from Ux to Aj
b = 8
c = 16
a^2 = 8^2 + 16^2 - 2*8*16*cos(45)
a^2 = 64 + 256 - 256(.707)
Do the math
a = {{{sqrt(139)}}}
a = 11.8 km from Aj to Ux
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