Question 1037823
three numbers form a geometric progression if we double the middle number we get an arithmetic progression the common ratio of the geometric progression is ?
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Original Progression:: a, ar, ar^2
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New Progression:: a, 2ar, ar^2
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Common ratio:: Divide 2nd term by 1st to get:: (2ar)/a = 2r
Divide the 3rd term by the 2nd to get:: (ar^2)/(2ar) = r/2
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If 2r = r/2 , 4r = r
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Comment:: Your problem statement doesn't make much sense.
Cheers,
Stan H.
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