Question 1037833
*[illustration sum2.JPG].
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In your case, {{{x=2a}}}, {{{y=3b}}}
{{{8a^3+27b^3=(2a+3b)(4a^2-(2a)(3b)+9b^2)}}}
{{{8a^3+27b^3=(2a+3b)(4a^2-6ab+9b^2)}}}
Nope, not too long, just right.