Question 1037757
If the chance of an overnight freeze in Rexburg on any given night is 0.55, what is the probability that it will freeze one or more of the next 8 nights in Rexburg? 
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Binomial problem with n = 8 ; p(freeze) = 0.55 ; p(not freeze) = 0.45
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P(1<= freeze <=8) = 1 - P(freeze = 0) = 1 - 0.45^8 = 0.9983
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Cheers,
Stan H.
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